ANSWER: The guidelines your discover including the one to you estimate use only when the fees will be looked at as an ongoing liquid that give in itself out on any surface, no matter what higher, and also have no thickness. Naturally, a case as you establish, that have 5 continuously electrons is within not a way including a fluid and that i would reckon that everything from 5-0 to help you 0-5 could be the delivery more an occasion. The theory is that, the five electrons do strategy on their own in order that for each is due to the fact at a distance throughout the other cuatro that you could, however, indeed there would not be a different sort of like distribution.
QUESTION: Would it be you can easily to suspend an electron via electrostatic levitation inside a good uniform magnetized field? Incase the fresh current try reduced sufficient so the electrostatic push for the electron is actually below the latest push on account of this new electron’s lbs create new electron upcoming sense a good ‘fall’ owed in order to gravity?
I’m asking this because I’m thinking when the setting a beneficial positron within the an effective consistent magnetic field (into the vacuum pressure) and you can lowering the current to a highly quick worthy of so as that the brand new electrostatic force is gloomier as compared to pounds create lead to good positron so you can including feel an excellent ‘fall’. And when they performed sense an autumn it can be determined when it do slip up otherwise down.
By the inertial bulk After all the brand new ratio of the push you affect it separated by the their velocity, quite simply the resistance to getting expidited
I am 17 years of age along with the united kingdom going to data physics at university for the sep and was just interested in learning so it since the our information this current year try electric phenomena and you can i chatted about millikan’s oils drop experiment hence seemed the same variety of suspension system in the event that electrostatic push and you may force on account of gravity were balanced.
Now, it is known to help you over the top precision the inertial bulk from good positron is equal to the fresh new inertial size from an enthusiastic electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a «magnetic field» you should say «electric field»; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever «weighed» a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 Atheist dating service -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.